# The area of the t

Given:

Equation 1: y = x Equation 2: x = 6 Equation 3: y = 0

According to the given question Equation 1 , 2 & 3 cuts each other at three different points creating a triangle and we need to calculate the area of this triangle formed by these lines.

Now Equation 2 is a line parallel to Y axis at a distance of 6 units. Equation 3 is the equation of the x axis.

So we can say that equation 2 & 3 are mutually perpendicular to each other and the triangle formed by these 3 equations is a right angled triangle .

We solve equation 1 & 2 by substitution method

After solving we get x = 6 & y = 6

So the perpendicular height of the triangle turns out to be 6 units.

Since Equation 2 is at a distance of 6 units from the origin so the length of the base turns out to be 6 units.

Perpendicular height = 6 units

Base Length = 6 units.

Area of the Triangle = * (perpendicular length) * (base length)

Area of the triangle becomes = * 6 *6 = 18 sq.units

The Area of the triangle is 18 sq. units

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