Q. 13

Solve the followi

Given, A differential equation (1 + y2) (1 + log x) dx + x dy = 0

To Find: find the solution of given differential equation

Explanation: we have (1 + y2) (1 + log x) dx + x dy = 0

It can be written as:

x dy= - (1 + y2) (1 + log x) dx

Now, Integrate both sides, we get

We know, , then

Now,

let 1 + log x = t , then

Putting the value of t , we get

Hence, This is the solution of given differential equation.

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