Answer :

Given, A differential equation (1 + y2) (1 + log x) dx + x dy = 0

To Find: find the solution of given differential equation


Explanation: we have (1 + y2) (1 + log x) dx + x dy = 0


It can be written as:


x dy= - (1 + y2) (1 + log x) dx




Now, Integrate both sides, we get



We know, , then



Now,


let 1 + log x = t , then





Putting the value of t , we get



Hence, This is the solution of given differential equation.


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