# Line segments AB and CD intersect at O such that AC || DB. If ∠CAB = 45° and ∠CDB =55°, then ∠BOD =A. 100°B. 80°C. 90°D. 135°

AC BD

CDB = 55o

2 = 45o

In

BOD + 2 + CDB = 180o

BOD + 45o + 55o = 180o

BOD + 100o = 180o

BOD = 180o – 100o

= 80o

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