Q. 133.5( 4 Votes )

Line segments AB and CD intersect at O such that AC || DB. If CAB = 45° and CDB =55°, then BOD =
A. 100°

B. 80°

C. 90°

D. 135°

Answer :

AC BD

CAD = 45o


CDB = 55o


2 = CAD (Alternate angle)


2 = 45o


In


BOD + 2 + CDB = 180o


BOD + 45o + 55o = 180o


BOD + 100o = 180o


BOD = 180o – 100o


= 80o

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