Q. 135.0( 1 Vote )

# Let y=(logx)

Given Data:

y=(logx)x+ xxcosx Let u = (logx)x and v = xxcosx Considering u = (logx)x

Taking log,

logu = x log(logx)

Differentiating w.r.t x,   Considering v = xxcosx

Taking log,

logv=x cosx logx

Differentiating w.r.t x,   Now y = u + v Using the above values, OR

Given Data:

x= a sin(pt), y=b cos(pt)

Differentiating w.r.t t  Now divide 2nd equation with 1st, we get Again differentiating w.r.t x we get Using the above value, we get  At t = 0, sec 0 =1 Rate this question :

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