Q. 135.0( 1 Vote )

# Let y=(logx)

Given Data:

y=(logx)x+ xxcosx

Let u = (logx)x and v = xxcosx

Considering u = (logx)x

Taking log,

logu = x log(logx)

Differentiating w.r.t x,

Considering v = xxcosx

Taking log,

ā logv=x cosx logx

Differentiating w.r.t x,

Now y = u + v

Using the above values,

OR

Given Data:

x= a sin(pt), y=b cos(pt)

Differentiating w.r.t t

Now divide 2nd equation with 1st, we get

Again differentiating w.r.t x we get

Using the above value, we get

At t = 0, sec 0 =1

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