Q. 135.0( 2 Votes )

# Let be a ray and let and be two rays on the same side of , with between and . Let be the bisector of ∠AOB. Prove that

∠XOA + ∠XOB = 2∠XOC

Answer :

⇒ ∠XOA + ∠XOB

⇒ ∠XOA (∠XOA + ∠AOB)

⇒ 2∠XOA + 2∠AOC

⇒ 2(∠XOA + ∠AOC)

⇒ 2∠XOC

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