Answer :

**NOTE:** Area of square = (side)^{2}

Area of circle = πr^{2}, where ‘r’ is radius of the circle.

i) Given, ABCD is a square

The length of the radius of circle = 7 cm

Diameter of the circle = 14cm

Let the side of square ABCD = x cm

By Pythagoras theorem (being a square there is angle of 90° between two adjacent sides)

AB^{2} + BC^{2} = AC^{2}

⇒ x^{2} + x^{2} = 14^{2}

⇒ 2 x^{2} = 196

⇒ x^{2} = 98

⇒ Area of square = x^{2} = 98cm^{2}

Area of circle = πr^{2} where r is the radius of the circle

=

⇒ Area of circle = 154 cm^{2}

Area of shaded region = area of circle – area of square

= 154 – 98 cm^{2}

= 56 cm^{2}

ii) Given, Radius of each circle = 3.5cm

And A,B, C, D are center of each circle

Hence, ABCD forms a square with each side of 7cm length

Area of square = (side)^{2}

= 7^{2} = 49 cm^{2}

Area of each circle = π r^{2}, where r is the radius of circle

=

Area of four circle = 4× area of each circle

= 4 × 38.5 = 154 cm^{2}

Area of shaded region = area of four circles – area of square

= 154 – 49 cm^{2}

= 105 cm^{2}

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