Q. 135.0( 4 Votes )

In the given figure, AB || CD and EF is a transversal, cutting them at G and H respectively. If EGB = 35° and QP EF, find the measure of PQH.


Answer :

EGB = QHP (Alternate Exterior Angles) = 35O


QPH = 90O


So, in triangle QHP we have,


QPH + QHP + PQH = 180O


90O + 35O + PQH = 180O


PQH = 180O – 90O – 35O


= 55O


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