Q. 133.7( 3 Votes )

In the figure, AD =

Answer :

    Since AD = BE
... AD + DB = BE + DB
        ⇒ AB = DE
Now in ΔABC and ΔEDF 
            AB = DE ...... (proved above)
            BC = DF ...... (given)
  and ∠ABC = ∠EDF ...... (given)
     ... ΔABC ≅ ΔEDF
        ... AC = EF ...... (c.p.c.t.)
  and ∠BAC = ∠DEF
but these are alternate interior angles of AC and EF with transversal AE 
... AC ïï EF

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Revision on Angle sum Property of TrianglesRevision on Angle sum Property of TrianglesRevision on Angle sum Property of Triangles44 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses