Q. 134.4( 15 Votes )

In Fig. 9.42, side BC of Δ ABC is produced to point D such that bisectors of ABC and ACD meet at a point E. If BAC = 68°, find BEC.


Answer :

By exterior angle theorem,

ACD = A + B


ACD = 68o + B


ACD = 34o + B


34o = ACD - EBC (i)


Now,


In


ECD = EBC + E


E = ECD - EBC


E = ACD - EBC (ii)


From (i) and (ii), we get


E = 34o


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