# In Fig. 9.42, side BC of Δ ABC is produced to point D such that bisectors of ∠ABC and ∠ACD meet at a point E. If ∠BAC = 68°, find ∠BEC.

By exterior angle theorem,

ACD = A + B

ACD = 68o + B

ACD = 34o + B

34o = ACD - EBC (i)

Now,

In

ECD = EBC + E

E = ECD - EBC

E = ACD - EBC (ii)

From (i) and (ii), we get

E = 34o

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Angle Sum Property of Triangle40 mins
Quiz | Lines and Angles43 mins
Quiz | Lines and Angles40 mins
NCERT | Angle Sum Property44 mins
Lines and Angles45 mins
Matter and Its Classification34 mins
NCERT | Intersecting and Non Intersecting lines)41 mins
NCERT | Discussion on Lines And Angles45 mins
Know About Transversal and Parallel lines42 mins
Champ Quiz | Triangle Inequality27 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses