Q. 134.4( 15 Votes )

In Fig. 9.42, side BC of Δ ABC is produced to point D such that bisectors of ABC and ACD meet at a point E. If BAC = 68°, find BEC.

Answer :

By exterior angle theorem,

ACD = A + B

ACD = 68o + B

ACD = 34o + B

34o = ACD - EBC (i)





E = ACD - EBC (ii)

From (i) and (ii), we get

E = 34o

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