Q. 134.6( 14 Votes )

# In Δ ABC, if ∠A=40° and ∠B=60° . Determine the longest and shortest sides of the triangle.

Given that in Δ ABC

A = 40o and B = 60o

We have to find shortest and longest side.

We know that,

Sum of angles of triangle = 180o

A + B + C = 180o

40o + 60o + C = 180o

100o + C = 180o

C = 180o – 100o

= 80o

Now,

40o < 60o < 80o

A < B < C

C is greater angle and A is smaller angle.

As, A < B < C

BC < AC < AB (Therefore, side opposite to greater angle is larger and side opposite to smaller angle is smaller)

Therefore, AB is longest, and BC is smallest or shortest side.

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