Answer :
For equal class intervals, we will solve by finding mid points of these classes using direct method.
We have got
Σfi = 39 + p and Σfixi = 2370 + 30p
∵ mean is given by
⇒ 
(∵ given: mean of pocket allowance is 54)
⇒ 2106 + 54p = 2370 + 30p
⇒ 54p – 30p = 2370 – 2106
⇒ 24p = 264
⇒ p = 11
Thus, p is 11.
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