Answer :
The figure will be drawn as
Since, point A is equidistant from points B and C. We can write in the form,
BA = AC …(i)
Now, length BA = 
And length AC = 
Substituting lengths BA and AC in equation (i), we get
Squaring both sides, we get
(3 – 0)2 + (p – 2)2 = (0 – p)2 + (2 – 5)2
⇒ 9 + p2 + 4 – 4p = p2 + 9
⇒ 4p = 4
⇒ p = 1
Hence, the value of p is 1.
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