Q. 13

From the top of a

Answer :


Let CD be a lighthouse such that CD = 75 m


And A and B be two ships with A directly behind B on same side of lighthouse.


To find distance between two ships = AB


Now,


Angle of depression for ship A, θ1 = 30°


Angle of depression for ship B, θ2 = 45°


Also,


CAD = θ1 = 30° [Alternate Angles]


CBD = θ2 = 45° [Alternate Angles]


Now, In ΔACD





AC = 75√3 m


In ΔBCD





BC = 75 m


Therefore,


AB = AC - BC


= 75√3 - 75


= 75(√3 - 1) m

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

At a point A, 20 Mathematics - Board Papers

If <img style="veRD Sharma - Mathematics

From a point on tMathematics - Board Papers

Evaluate each of RD Sharma - Mathematics

Express <imRD Sharma - Mathematics