Q. 135.0( 4 Votes )

Find the value of

Answer :

Given;

PA = PB

P (2, 4)

A (5, k)

B (k, 7)

By squaring both sides;

PA2 = PB2

(5 – 2)2 + (k – 4)2 = (k – 2)2 + (7 – 4)2

9 + (k – 4)2 = (k – 2)2 + 9

9 + (k – 4)2 – (k – 2)2 = 9

(k – 4)2 – (k – 2)2 = 9 – 9

(k – 4)2 – (k – 2)2 = 0

[k2 – (4)2 + 8k]- [k2 – (2)2 + 4k] = 0 ……{by (a-b)2 = a2 – b2 + 2ab}

k2 – 16 + 8k – k2 + 4 – 4k = 0

- 12 + 4k = 0

4k = 12

k = 12/4 = 3

Therefore the value of k is 3.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Glimpses of India39 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Which of the follRS Aggarwal - Mathematics

Which of the follRS Aggarwal - Mathematics

Which of the follRS Aggarwal - Mathematics

Solve each of theRS Aggarwal - Mathematics

Solve each of theRS Aggarwal - Mathematics

Solve each of theRS Aggarwal - Mathematics

Solve each of theRS Aggarwal - Mathematics