# Find the distance

Given the equation of a line: x = 3λ + 2 ; y = 4λ – 1 and z = 12λ + 2 where λ is any real number.

(3λ + 2 , 4λ – 1 , 12λ + 2) gives coordinate of a random point which lies on the given line.

At the point of intersection of plane and line, points will be lying on plane too.

So they will satisfy the equation of plane: x – y + z = 5

3λ + 2 – (4λ - 1) + (12λ + 2) = 5

11λ + 5 = 5

λ = 0

Thus point of intersection is (2,-1,2)

But we need to find the distance between (-1,-5,-10) and (2,-1,2)

Distance between two points (x1,y1,z1) and (x2,y2,z2) is given by-

D = D = D = Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Find the equationMathematics - Board Papers

Find the equationMathematics - Board Papers

Find the length oMathematics - Board Papers

Find the coordinaMathematics - Board Papers

Find the equationMathematics - Board Papers

Show that the linMathematics - Board Papers