Q. 133.8( 4 Votes )

Evaluate th

Answer :

We have,


I=


Let f(x) = sin|x| + cos|x|


Then, f(x) =f(–x)


Since, (f(x) is an even function.


So, I=


=


=


=


= 2[0 + 1 + 1–0]


= 2(2)


Hence, = 4

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