Q. 134.3( 8 Votes )

# Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.

Answer :

Steps of Construction:

(i) Draw base, BC = 5 cm

Now, draw a ray BX such that ∠XBC = ∠B = 60°.

(ii) Here, sum of two sides = AB + AC = 7.5 cm

So, cut the line segment BD = 7.5 cm from ray BX.

(iii) Join DC.

(iv)Draw perpendicular bisector of DC, say PQ, which intersects BD at A.

(v) Now join AC.

Thus, we get a ΔABC which is the required triangle.

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