Q. 134.3( 8 Votes )
Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.
Steps of Construction:
(i) Draw base, BC = 5 cm
Now, draw a ray BX such that ∠XBC = ∠B = 60°.
(ii) Here, sum of two sides = AB + AC = 7.5 cm
So, cut the line segment BD = 7.5 cm from ray BX.
(iii) Join DC.
(iv)Draw perpendicular bisector of DC, say PQ, which intersects BD at A.
(v) Now join AC.
Thus, we get a ΔABC which is the required triangle.
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