At a point A, 20
The above diagram represents the problem in which C is the position of the cloud and D is the position of cloud's shadow.
Let AB = x
Let BC = h
As cloud is at a height of (20 + h) m from the water level. Its shadow will be (20 + h)m deep in the water.
So we have
BD = 20 + (20 + h) = (40 + h) mimpl
Now in △ABC
3h = h + 40
h = 20 m
Distance of point A from Cloud C = AC
By phythagoras theorm in triangle ABC
(AC)2 = (AB)2 + (BC)2
Implies AC = 40 m
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