Q. 12 D5.0( 4 Votes )

# If (3x – 1)7 = a7x7 + a6x6 + a5x5 + ………..+ a1x + a0, then let us write the value of a7 + a6 + a5 + …….. a0 (where a7, a6 ……………a0 are constants)

We have been given that,

(3x – 1)7 = a7x7 + a6x6 + a5x5 + … + a1x + a0

If we simply put x = 1 in the above equation,

(3(1) – 1)7 = a7(1)7 + a6(1)6 + a5(1)5 + …+ a1(1) + a0

⇒ a7 + a6 + a5 + … + a1 + a0 = (3 – 1)7

⇒ a7 + a6 + a5 + … + a1 + a0 = 27

⇒ a7 + a6 + a5 + … + a1 + a0 = 128

Thus, value of a7 + a6 + a5 + … + a1 + a0 = 128.

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