Let us calculate

We have the polynomial as k²x³ – kx² + 3kx – k.

Given that x - 3 is the factor of the polynomial, which means that x = 3 is the root of the polynomial.

So f(3) = 0.

k²(3)³ – k(3)² + 3k(3) – k = 0

27k² – 9k + 9k – k = 0

27k² – k = 0

k(27k – 1) = 0

k= 0 or

⸫ value of k is 0 or .