Q. 12 B4.9( 10 Votes )

# Let us calculate

We have the polynomial as k2x3 – kx2 + 3kx – k.

Given that x - 3 is the factor of the polynomial, which means that x = 3 is the root of the polynomial.

So f(3) = 0.

k2(3)3 – k(3)2 + 3k(3) – k = 0

27k2 – 9k + 9k – k = 0

27k2 – k = 0

k(27k – 1) = 0

k= 0 or value of k is 0 or .

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