For the given compound, the number of π-electrons is 6.
By Huckel’s rule,
4n + 2 = 6
⇒ 4n = 4
⇒ n = 1
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2…).
In this case, the value of n is 1 which is an integer, hence the given compound is aromatic in nature.
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