# Using properties

Given:

To find: the value of x using the properties of determinants

Let

Now we will apply the operation, R1 R1+R2+R3, we get

Taking (3x+a) common we get

Now we will apply the operation, C1 C1-C3, we get

Now we will apply the operation, C2 C2-C3, we get

Now we will expand along R1, we get

Δ=(3x+a)[1{(0)(-a)-(-a)(a)}]

Δ=(3x+a)[1(0+a2)]

Δ=a2 (3x+a)

Δ=a2 (3x+a)

But Given Δ=0

So,

a2 (3x+a)=0

(3x+a)=0

Hence this is the required values of x

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Prove the followiMathematics - Board Papers