Q. 123.7( 6 Votes )

The incircle of a

Answer :

Given an isosceles triangle ABC.



Also given AB = AC


So, BF + AF = AE + EC … (1)


From the diagram, AB, BC and CA are tangents to the circle at F, D and E respectively.


BF = BD, AE = AF and CE = CD … (2)


From (1) and (2),


BD + AE = AE + CD


BD = CD


Hence proved.


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