Answer :

As we know

four cards are drawn from the remaining 40 cards, so we have to find the probability that all of them belong to different suit

total possible outcomes of drawing four cards are ^{40}C_{4}

therefore n(S)= ^{40}C_{4}

let E be the event that 4 cards belong to different suit

n(E)= ^{10}C_{1}× ^{10}C_{1}×^{10}C_{1}×^{10}C_{1}

= 10× 10× 10× 10

=10000

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