Answer :

**Concept Used:** Circumference of the base of the cylinder = 2πr

Outer Surface Area of cylinder = 2πrh

Where r = radius of the cylinder and h = height of the cylinder.

**Given:** r + h = 41 cm

Circumference of the base of cylinder = 2πr = 132 cm

**Explanation:**

Let us calculate the value of “r” first,

2πr = 132 cm

r = (3 × 7) cm

r = 21 cm.

Now, let us calculate the height of the cylinder,

r + h = 41

Putting the obtained value of “r” we get,

21 + h = 41

h = 20 cm

Now putting the values of “r” and “h” in the formula of Outer Surface Area of the cylinder we get,

The outer surface area of cylinder = 2πr

The outer surface area of cylinder

The outer surface area of cylinder = 120 × 22

The outer surface area of cylinder = 2640 cm^{2}

**Hence, the outer surface area of a cylinder is 2640 cm ^{3}.**

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