1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 A 17 B 17 C 17 D 17 E 18 A 18 B 18 C 18 D 18 E

West Bengal Mathematics

15. Area and Perimeter of Triangle and Quadrilateral Shaped Region

1. Real Numbers
2. Laws of Indices
3. Graph
4. Co-ordinate Geometry: Distance Formula
5. Linear Simultaneous Equations
6. Properties of Parallelogram
7. Polynomial
8. Factorisation
9. Transversal and Mid-Point Theorem
10. Profit and Loss
11. Statistics
12. Theorems on Area
13. Construction: (Construction of a Parallelogram whose measurement of one angle is given and equal in area of a triangle)
14. Construction: (Construction of a triangle equal in area of a quadrilateral)
15. Area and Perimeter of Triangle and Quadrilateral Shaped Region
16. Circumference of Circle
17. Theorems on concurrence
18. Area of Circular Region
19. Co-ordinate Geometry: Internal and External Division of Straight Line Segment
20. Co-ordinate Geometry: Area of Triangular Region
21. Logarithm

Let us Do 15.1

Let us do yourself 15.2

Let us do 15.3

Let us do the sum 15.1

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 A 19 B 19 C 19 D 19 E 20 A 20 B 20 C 20 D 20 E

Calculate and See 15.2

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 A 21 B 21 C 21 D 21 E 21 F 22 A 22 B 22 C 22 D 22 E

Let us see by calculating 15.3

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 A 17 B 17 C 17 D 17 E 18 A 18 B 18 C 18 D 18 E

Q. 124.3( 4 Votes )

Sahin draws a tra

Class 9th West Bengal Mathematics 15. Area and Perimeter of Triangle and Quadrilateral Shaped Region

Answer :

Given, a trapezium ABCD of which length of diagonal BD is 11 cm

And two perpendicular of which length are 5 cm and 11 cm respectively from the points A and C on the diagonal BD.

According to the figure the area of the trapezium = area of ∆ABD + area ∆BCD

= ×BD×AM + ×BD×CN

= ×11×5 + ×11×11

= 27.5 + 60.5

= 88 sq. cm.

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