Q. 124.2( 19 Votes )

Polynomials bx2 + x + 5 and bx3 – 2x + 5 are divided by polynomial x – 3 and the remainders are and respectively. If m – n =0 then find the value of b.

Answer :

Put x = 3 in the first polynomial:

b× (3)2 + 3 + 5 = m


9b + 8 = m ………………………………….. (i)


Put x = 3 in the second polynomial


b× (3)3 -2× 3 + 5 = n


27b -6 + 5 = n


27b -1 = n …………………………………. (ii)


Equation (i) – (ii)


m –n = 9b + 8 – (27b -1)


but m-n = 0


9b + 8 -27b + 1 = 0


-18b + 9 = 0


18b = 9


b = 9/18


b = 1/2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz | Polynomials29 mins
Methods to find zeroes of a Polynomial-246 mins
Remainder Theorem and Factor Theorem38 mins
Polynomials - Zero to Hero42 mins
Genius Quiz | Polynomials40 mins
Zeros and Degrees of a Polynomial41 mins
Introduction to Polynomials37 mins
Quiz | Imp. Qs. on Algebraic Identities65 mins
Basic understanding of Polynomials37 mins
QUiz on Previous year NTSE Questions45 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :