Q. 125.0( 1 Vote )

# O is any point in the interior of ∆ABC. Then, which of the following is true?

A. (OA+OB+OC)> (AB+BC+CA)

B. (OA+OB+OC) >(AB+BC+CA)

C. (OA+OB+OC) < (AB+BC+CA)

D. None of these

Answer :

From the given question, we have

In ∆OAB, ∆OBC and ∆OCA we have:

OA + OB > AB

OB + OC > BC

And, OC + OA > AC

Adding all these, we get:

2 (OA + OB + OC) > (AB + BC + CA)

(OA + OB + OC >

∴ Option (C) is correct

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