Q. 125.0( 2 Votes )
In the given figure, BE ⊥ AC, ∠DAC = 30° and ∠DBE = 40°. Find ∠ACB and ∠ADB.
Answer :
In triangle BEC we have,
B = 40O and 
E = 90O
So,
C = 180O – (90 + 40)
=50O
Therefore,
ACB = 50O
Now intriangle ADC we have,
A = 30O and 
C = 50O
So,
D = 180O – (30 + 50)
=100O
Therefore,
ADB + 
ADC = 180 (sum of angles on straight line)
ADB + 100 = 180
ADB = 180 – 100
= 80O
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