Q. 125.0( 2 Votes )

In the given figure, BE AC, DAC = 30° and DBE = 40°. Find ACB and ADB.


Answer :

In triangle BEC we have,


B = 40O and E = 90O


So,C = 180O – (90 + 40)


=50O


Therefore,ACB = 50O


Now intriangle ADC we have,


A = 30O and C = 50O


So,D = 180O – (30 + 50)


=100O


Therefore,


ADB + ADC = 180 (sum of angles on straight line)


ADB + 100 = 180


ADB = 180 – 100


= 80O


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