# In the given figure, BE ⊥ AC, ∠DAC = 30° and ∠DBE = 40°. Find ∠ACB and ∠ADB.

In triangle BEC we have,

B = 40O and E = 90O

So,C = 180O – (90 + 40)

=50O

Therefore,ACB = 50O

A = 30O and C = 50O

So,D = 180O – (30 + 50)

=100O

Therefore,

= 80O

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