# In the given figu

In triangle BEC we have, B = 40O and E = 90O

So, C = 180O – (90 + 40)

=50O

Therefore, ACB = 50O A = 30O and C = 50O

So, D = 180O – (30 + 50)

=100O

Therefore, ADB + ADC = 180 (sum of angles on straight line) ADB + 100 = 180 ADB = 180 – 100

= 80O

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