Q. 125.0( 2 Votes )

In the given figu

Answer :

In triangle BEC we have,

B = 40^O and E = 90^O

So,C = 180^O – (90 + 40)

=50^O

Therefore,ACB = 50^O

Now intriangle ADC we have,

A = 30^O and C = 50^O

So,D = 180^O – (30 + 50)

=100^O

Therefore,

ADB + ADC = 180 (sum of angles on straight line)

ADB + 100 = 180

ADB = 180 – 100

= 80^O

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