Answer :

Given :

AD = 5 cm

DB = 8 cm

AC = 6.5 cm

DE ||BC

In ΔABC & ΔADE

∠ADE = ∠ABC (Corresponding Angles)

∠AED = ∠ACB (Corresponding Angles)

So ΔABC & ΔADE are similar by the A.A. (Angle-Angle) axiom of Similarity

AB = AD + BD = 13 cm.

Since the two triangles are similar so their lengths of sides must be in proportion.

⇒

⇒

__AE = 2.5cm.__

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