Answer :

Given :


AD = 5 cm


DB = 8 cm


AC = 6.5 cm


DE ||BC


In ΔABC & ΔADE


ADE = ABC (Corresponding Angles)


AED = ACB (Corresponding Angles)


So ΔABC & ΔADE are similar by the A.A. (Angle-Angle) axiom of Similarity


AB = AD + BD = 13 cm.


Since the two triangles are similar so their lengths of sides must be in proportion.




AE = 2.5cm.


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