AD = 5 cm
DB = 8 cm
AC = 6.5 cm
In ΔABC & ΔADE
∠ADE = ∠ABC (Corresponding Angles)
∠AED = ∠ACB (Corresponding Angles)
So ΔABC & ΔADE are similar by the A.A. (Angle-Angle) axiom of Similarity
AB = AD + BD = 13 cm.
Since the two triangles are similar so their lengths of sides must be in proportion.
AE = 2.5cm.
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