Answer :
Given:
n=5
p(x=2)=9p(x=3)
p=?
P(x=r)= nCr pr qn-r
P(x=1)= 5C1 p1 q4
= 5p q4
P(x=3)= 5C3 p3 q2
= 20 p3 q2
Put values in equation, we have:
5p q4= 9(20 p3 q2)
q2= 9(4 p2)
(1-p)2= 36p2
1+p2-2p= 36p2
35p2+2p-1=0
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
A box has 100 pen
Mathematics - ExemplarState True or Fal
Mathematics - ExemplarA random variable
Mathematics - Board PapersHow many times mu
Mathematics - Board PapersA card from a pac
Mathematics - Board PapersAn experiment suc
Mathematics - Board PapersA bag A contains
Mathematics - Board PapersOn a multiple cho
Mathematics - Board PapersMark the correct
RD Sharma - Volume 2