Answer :

Let ABC is an acute angled triangle.

B = 90o

We know that,

A + B + C = 180o

A + 90o + C = 180o

A + C = 90o (i)


AOC + ACD + CAD = 180o

AOC + C + A = 180o

AOC + (A + C) = 180o

AOC + * 90o = 180o [From (i)]

AOC + 45o = 180o

AOC = 180o – 45o

= 135o

Thus, the angle at O between two bisectors is equal to 135o.

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