Q. 125.0( 1 Vote )

If ABC is an equilat

Answer :

 
Given: Δ ABC is an equilateral triangle of side 2a. AD is the altitude of the triangle.
To Prove: AD = a√ 3 and 3AB2 = 4AD2
Proof:
In rt. Δ ADC,
AD2 = AC2 - DC2
    = (2a)2 - a2
    = 4a2 - a2
    = 3a2
AD = a𢆣
3AB= 3(2a)2
     = 3(2a)2
     = 3 ´ 4a2
     = 4(a√ 3)2
     = 4AD2
∴ 3AB2 = 4AD2.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Draw the graph ofNCERT - Mathematics