Answer :

The numbers divisible by 6 will form an arithmetic progression with common difference 6

First two-digit no. divisible by 6 is 12 = a_{1}

last two-digit no. divisible by 6 is 96 = a_{n}

Therefore, we have to find number of terms in AP 12, 18, …, 96

Here, First term, a = 12

Common difference, d = 96

nth term = 96

We know, nth term of an AP is a_{n} = a_{1} + (n – 1)d

⇒ 96 = 12 + (n – 1)6

⇒ 84 = (n – 1)6

⇒ n – 1 = 14

⇒ n = 15

∴ 15 two-digit no are divisible by 6

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Glimpses of India39 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation