Q. 125.0( 1 Vote )

How many times mu

Answer :

Given; Tossing of a fair coin;


Let p be the probability of getting a head and q be the probability of getting a tail.



Let X be the random variable denoting the number of tosses.


According to the given condition:


P(X≥1) = 1 − P(X<1) >80%


P(X<1) < 1 − 0.8


P(X = 0) < 0.2




2n > 5


n ≥ 3


The man should toss a fair coin minimum 3 times so that the probability of having at least one head is more than 80%


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