Q. 125.0( 1 Vote )

How many times mu

Answer :

Given; Tossing of a fair coin;

Let p be the probability of getting a head and q be the probability of getting a tail.

Let X be the random variable denoting the number of tosses.

According to the given condition:

P(X≥1) = 1 − P(X<1) >80%

P(X<1) < 1 − 0.8

P(X = 0) < 0.2

2n > 5

n ≥ 3

The man should toss a fair coin minimum 3 times so that the probability of having at least one head is more than 80%

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