Q. 125.0( 1 Vote )

# Find the value of

Now,

F(x) is continuous at x=2

If L.H.L=R.H.L=f(2)

Then,

L.H.L

5

R.H.L

2a + b

Since, L.H.L=R.H.L

2a + b=5 …(i)

Now,

F(x) is continuos at x=10

If L.H.L=R.H.L=f(10)

L.H.L

10a + b

R.H.L

21

Since, L.H.L=R.H.L

10a + b=21 …(ii)

Now, From (i) and (ii)

10a + (5 - 2a)=21

8a=16

a=2

Putting the value of a in equation (i)

2(2) + b=5

4 + b=5

B=5 - 4

b=1

Hence, The value of a = 2 and b=1

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