Q. 124.3( 6 Votes )
Find the smallest nu
9408 = 2x2x2x2x2x2x3x7x7
The prime factors 2 and 7 occur in pairs.
But prime factor 3 doesn't have a pair.
Therefore, 3 is the smallest number by which 9408
must be divided so that it becomes a perfect square.
... Perfect square = 9408/3= 3136
... Square root = 2x2x2x7= 56
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