# Find the area of a rhombus each side of which measurers 20 cm and one of whose diagonals is 24 cm.

Given:

Length of diagonal 1 (d1) = 24 cm

Side = 20 cm

Let, Length of diagonal 2 be d2

We know that,

Side of rhombus = 1/2 × √(d12 + d22 )

20 = 1/2 × √(242 + d22 )

20 × 2 = √(576 + d22 )

40 = √(576 + d22)

Squaring both sides,

1600 = 576 + d22

d22 = 1600-576

d22 = 1024

d2 = 32 cm

Now,

Area of rhombus= 1/2 × d1 × d2

= 1/2 × 24 × 32

= 384 cm2

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