Answer :

To find: differentiation of with respect to x

⇒ y = a + b

Taking log both the sides:

{∵ log x^{a} = alog x}

Differentiating with respect to x:

Taking log both the sides:

{log x^{a} = alog x}

Differentiating with respect to x:

Hence, differentiation of (x.cos x)^{x} + with respect to x is (x cos x)^{x}{1 – x tan x + log(x cos x)} +

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