Answer :

Let R be the radius of outer circumference and r be the radius of inner circumference

Outer circumference of circular field = 2π R

And inner circumference of circular field = 2π r

Given,

Length of Outer circular field – length of inner circular field = 132m

circumference of circular field - circumference of circular field = 132 m

⇒ 2π (R- r) = 132m

⇒

⇒R – r = 21 m

This is the radius of the circular path

Given, area of path = 14190 m^{2}

⇒ π (R- r)^{2} = 14190

⇒

⇒ (R-r) = √ 4515

⇒ Radius of circular path = 67.19 m

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