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S = {(1,1), (1,2), .....(6,6)}

n(S) = 36

Let the first die be black die and second die be red die,

A = Red die resulted in a number less than 4.

= { (1,1), (1,2), (1,3), (2,1), (2,2), (2,3), (3,1), (3,2), (3,3), (4,1), (4,2), (4,3), (5,1), (5,2), (5,3), (6,1), (6,2), (6,3)}

Therefore, we can see that there are 18 possible outcomes when red die resulted in less than 4.

n(A) = 18

B = sum of number is 8

B = {(4,4), (6,2), (2,6), (5,3), (3,5)}

There are 5 possible outcomes when sum of number = 8

n(B) = 5

From A and B we can say that,

AB = {(5,3), (6,2)}

n(A B) = 2

P() = Probability of sum of numbers 8 when Red die resulted in a number less than 4

= .

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