# Two tailors, A an

Let A works for x days and B works for y days.

x ≥ 0, y ≥ 0

Minimum no. of shirts = 60

Given: A can stitch 6 shirts and 4 pairs of trousers while B can stitch 10 shirts and 4 pairs of trousers

6x + 10y ≥ 60

3x + 5y ≥ 30

Minimum no. of trousers = 32

4x + 4y ≥ 32

x + y ≥ 8

Let z be the total labor cost.

z = 300x + 400 y

the given L.P problem reduces to: z = 300x + 400y

x ≥ 0, y ≥ 0, 3x + 5y ≥ 30, x + y ≥ 8

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