# The sum of two angles of a triangle is 80° and their difference is 20°. Find the angles of the triangle.

In a triangle ABC, it is given that

A – B = 20° … (1)

and A + B = 80° .. (2)

2A = 100°

⇒ ∠A = 50°

So, B = 80° - A = 80° - 50° = 30°

We know that the sum of the angles of a triangle is 180°.

⇒ ∠A + B + C = 180°

50° + 30° + C = 180°

⇒ ∠C = 180° - 80°

⇒ ∠C = 100°

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