# The length x of a

Given: , and x = 8 cm and y = 6 cm

(a) Perimeter of rectangle

We know that perimeter of rectangle = 2 (l + b)

= 2 (x + y)

Differentiating both sides w. r. to t, we get = 2 (-5 + 4)

= -2 cm/min

Perimeter of rectangle is decreasing at the rate of 2 cm/min.

(b) Area of rectangle

We know that area of rectangle = lb

= xy

Differentiating both sides w. r. to t, we get = 8 (4) + 6 (-5)

= 32 – 30

= 2 cm2/min

Area of rectangle is increasing at the rate of 2 cm2/min.

OR

Given: f (x) = sin x + cos x, 0 ≤ x ≤ 2π

f’ (x) = cos x – sin x

We know that for stationary points, f’ (x) = 0

cos x – sin x = 0

tan x =1

x = π/4, 5π/4 as 0 ≤ x ≤ 2π

The points x = π/4 and x = 5π/4 divide the interval [0, 2π] into following disjoint intervals: (0, π/4), (π/4, 5π/4) and (5π/4, 2π) Here f is strictly increasing in the intervals (0, π/4) and (5π/4, 2π) and f is strictly decreasing in the interval (π/4, 5π/4).

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