Answer :


Let ABCD is a parallelogram.


The angle bisectors AE and BE of adjacent angles A and B meet at E.


AD || BC (Opposite sides of ||gm)


DAB + CBA = 180°


2EAB + 2EBA = 180° (sum of the interior angles, formed on the same side of the transversal, is 180°)


AE and BE are the bisectors of DAB and CBA respectively.


EAB + EBA = 90° ... (1)


In ∆EAB,


EAB + EBA + AEB = 180° (sum of the angles of a triangle is 180°)


90° + AEB = 180°


From (1)


AEB = 90°

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