Solve: 23x + 29y = 98, 29x + 23y = 110.
The given equations are 23x + 29y = 98, 29x + 23y = 110.
We know that the general form for a pair of linear equations in 2 variables x and y is a1x + b1y + c1 = 0
and a2x + b2y + c2 = 0.
Comparing with above equations,
we have a1 = 23, b1 = 29, c1 = - 98; a2 = 29, b2 = 23, c2 = - 110
We can solve by cross multiplication method using the formula
Substituting values in the formula, we get
⇒ x = 3 and y = 1
The solution is x = 3 and y = 1.
Rate this question :
Solve the following pair of linear equation by cross - multiplication method:
x + 4y + 9 = 0
5x – 1 = 3yKC Sinha - Mathematics
Solve each of the following systems of equations by using the method of cross multiplication:
2x + y = 35, 3x + 4y = 65.RS Aggarwal - Mathematics