Skakil draws an e

Given, PQR is an equilateral triangle

Let PQ = QR= PR = x cm and AC = 10cm, AB = 12 cm and AD = 8cm

Area of the equilateral triangle =

⇒ area of equilateral triangle PQR =

Here,

Area of triangle PQR = area of triangle PAR

+ area of triangle RAQ

+ area of triangle PAQ

= (∵ area of triangle= 1/2 ×base× height)

In this case the perpendicular is height of the that particular triangle

= 4x + 6x + 5x

According to the given condition

15x =

= x

Now

Area of equilateral triangle PQR =

= cm²

= cm²

= 300√3cm²