Q. 115.0( 3 Votes )

Mark the correct A. 0

B. 1

C. 2

D. 3

Answer :

sin6A + cos6A = (sin2A)3 + (cos2A)3


=(sin2A+ cos2A)(sin4A+cos4A-sin2Acos2A)


= 1 (sin4A + cos4A – sin2Acos2A)


sin4A + cos4A – sin2Acos2A+ 3 sin2 A cos2 A


sin4A + cos4A + 2sin2Acos2A


(sin2A + cos2A)2


= 12


=1

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