Q. 115.0( 3 Votes )
Mark the correct A. 0
B. 1
C. 2
D. 3
Answer :
sin6A + cos6A = (sin2A)3 + (cos2A)3
=(sin2A+ cos2A)(sin4A+cos4A-sin2Acos2A)
= 1 (sin4A + cos4A – sin2Acos2A)
∴ sin4A + cos4A – sin2Acos2A+ 3 sin2 A cos2 A
⇒ sin4A + cos4A + 2sin2Acos2A
⇒ (sin2A + cos2A)2
= 12
=1
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
True and False<br
Mathematics - ExemplarFind the values o
RD Sharma - MathematicsProve that :
<
The value of cos<
Mathematics - ExemplarThe value of sin
Mathematics - Exemplarcos 2θ cos 2<span
Mathematics - ExemplarThe value of <spa
Mathematics - ExemplarIf <span lang="EN
Mathematics - ExemplarIf <span lang="EN
Mathematics - ExemplarFill in the blank
Mathematics - Exemplar