Q. 114.8( 4 Votes )

In the given figure ABC and DBC have the same base BC such that AB = 120m, AC = 122m, BC = 22m, BD = 24m and CD = 26m. Find the area of the shaded region. (Take = 10.25)


Answer :

It is given in the question that,


AB = 120 m


AC = 122 m


BC = 22 m


BD = 24 m


And, CD = 26 m


We know that,


Perimeter of triangle = Sum of all sides


Perimeter of = AB + BC + AC


= 120 + 22 + 122


= 264 m


s =


=


= 132 m


Now, Area () =


=


=


= 11 × 12 × 10


= 1320 m2


Now, in


BC = a, BD = b and CD = c


Perimeter of = 22 + 24 + 26


= 72 m


s =


=


= 36 m


Hence, area ( =


=


=





= 24 × 10.25


= 246 m2


Area of shaded region = Area () – Area ()


= 1320 – 246


= 1074 m2


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