Q. 11

# In Fig. 9.40, if AB||CD, EF||BC, ∠BAC = 65° and ∠DHF = 35°, find ∠AGH.

Given,

AB CD and,

EF BC

BAC = 65o and DHF = 35o

BAC = ACD (Alternate angles)

ACD = 65o

DHF = GHC (Vertically opposite angles)

GHC = 35o

In

GCH + GHC + HGC = 180o

65o + 35o + HGC = 180o

HGC = 80o

AGH + HGC = 180o (Linear pair)

AGH + 80o = 180o

AGH = 100o

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